## Question

The in centre of the triangle with vertices , (0, 0) and (2, 0) is

### Solution

If the points be* A, B, C* then *AB = BC = CA = *2

is equilateral.

Hence the in center will coincide with the centroid.

#### SIMILAR QUESTIONS

*O *(0, 0), *A*(1, 1), *B*(0, 3) are the vertices of a triangle *OAB*.*P *divides *OB* in the ratio 1 : 2, *Q* is the mid-point of *AP, R *divides *AB* in the ratio 2 : 1

area of Δ*PQR* : area of Δ*OAB* is

*O *(0, 0), *A*(1, 1), *B*(0, 3) are the vertices of a triangle *OAB*.*P *divides *OB* in the ratio 1 : 2, *Q* is the mid-point of *AP, R *divides *AB* in the ratio 2 : 1

If *S* is the mid-point of *PR*, then *QS* is equal to

*a* and *b* real numbers between 0 and 1 *A*(*a*, 1), *B*(1, *b*) and*C*(0, 0) are the vertices of triangle

1:- If the triangle *ABC* is equilateral, its area is equal to

If the triangle *ABC* in isosceles with* AC = BC* and 5(AB)^{2} = 2(AC)^{2} then

The origin is shifted to(1, –2)then what are the coordinates be shifted if the point (3, –5) in the new position?

If the origin is shifted to (1, –2), the coordinates of *A* become (2, 3). What are the original coordinates of *A*?

Determiner as to what point the axes of the coordinates be shifted so as to remove the first degree terms from the equation

*f *(*x, y*) = 2*x*^{2} + 3*y*^{2} – 12*x* + 12*y *+ 24 = 0

What will be the coordinates of the point when the axes are rotated through an angle of 30^{0} in clockwise sense?

What will be the coordinates of the point in original position ifr its coordinates after rotation of axes through an angle 60^{0} ?

If a vertex of a triangle is (1, 1) and the mid-point of two sides through the vertex are (–1, 2) and (3, 2), then the centroid of the triangle is