# Line slope calculator 2x+y=22

**Straight line given by points A[6; 10] and B[7; 8]**

## Calculation:

**Slope-intercept form of line:**y = -2x+22

**Canonical form of the line equation:**2x+y-22 = 0

**Parametric form of the line equation:**

x = t+6

y = -2t+10 ; t ∈ R

**Slope:**m = -2

**Slope angle of line: φ =**-63°26'6″ = -1.1071 rad

**X intercept:**x

_{0}= 11

**Y intercept:**y

_{0}= q = 22

**Distance line from the origin:**d

_{0}= 9.8387

**The length of the segment AB: |AB| =**2.2361

**Vector: AB =**(1; -2)

**Normal vector: n =**(2; 1)

**Midpoint of the segment AB: M =**[6.5; 9]

**Perpendicular Bisector equation:**x-2y+11.5 = 0

**Vector OA = (6; 10) ; |OA| = 11.6619**

**Vector OB = (7; 8) ; |OB| = 10.6301**

**Scalar product OA .OB = 122**

**Angle ∠ AOB = 10°13'20″ = 0.1784 rad**